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cb::inverse
c
      program inverse
c
c********1*********2*********3*********4*********5*********6*********7**
c
c name:      inverse
c version:  200208.19
c author:    stephen j. frakes
c purpose:  to compute a geodetic inverse
c            and then display output information
c
c input parameters:
c -----------------
c
c output parameters:
c ------------------
c
c local variables and constants:
c ------------------------------
c answer          user prompt response
c b                semiminor axis polar (in meters)
c baz              azimuth back (in radians)
c buff            input char buffer array
c dd,dm,ds        temporary values for degrees, minutes, seconds
c dlon            temporary value for difference in longitude (radians)
c dmt,d_mt        char constants for meter units     
c edist            ellipsoid distance (in meters)
c elips            ellipsoid choice
c esq              eccentricity squared for reference ellipsoid
c faz              azimuth forward (in radians)
c filout          output file name
c finv            reciprocal flattening
c hem              hemisphere flag for lat & lon entry
c ierror          error condition flag with d,m,s conversion
c lgh              length of buff() array
c option          user prompt response         
c r1,r2            temporary variables 
c ss              temporary variable 
c tol              tolerance for conversion of seconds
c
c name1            name of station one
c ld1,lm1,sl1      latitude  sta one - degrees,minutes,seconds
c ald1,alm1,sl1    latitude  sta one - degrees,minutes,seconds
c lat1sn          latitude  sta one - sign (+/- 1)
c d_ns1            latitude  sta one - char ('N','S')
c lod1,lom1,slo1  longitude sta one - degrees,minutes,seconds
c alod1,alom1,slo1 longitude sta one - degrees,minutes,seconds
c lon1sn          longitude sta one - sign (+/- 1)
c d_ew1            longitude sta one - char ('E','W')
c iaz1,maz1,saz1  forward azimuth  - degrees,minutes,seconds
c isign1          forward azimuth  - flag  (+/- 1)
c glat1,glon1      station one      - (lat & lon in radians )
c p1,e1            standpoint one    - (lat & lon in radians )
c
c name2            name of station two
c ld2,lm2,sl2      latitude  sta two - degrees,minutes,seconds
c ald2,alm2,sl2    latitude  sta two - degrees,minutes,seconds
c lat2sn          latitude  sta two - sign (+/- 1)
c d_ns2            latitude  sta two - char ('N','S')
c lod2,lom2,slo2  longitude sta two - degrees,minutes,seconds
c alod2,alom2,slo2 longitude sta one - degrees,minutes,seconds
c lon2sn          longitude sta two - sign (+/- 1)
c d_ew2            longitude sta two - char ('E','W')
c iaz2,maz2,saz2  back azimuth      - degrees,minutes,seconds
c isign2          back azimuth      - flag  (+/- 1)
c glat2,glon2      station two      - (lat & lon in radians )
c p2,e2            forepoint two    - (lat & lon in radians )
c
c global variables and constants:
c -------------------------------
c a                semimajor axis equatorial (in meters)
c f                flattening
c pi              constant 3.14159....
c rad              constant 180.0/pi
c
c    this module called by:  n/a
c
c    this module calls:      elipss, getrad, inver1, todmsp
c    gethem, trim,  bufdms, gvalr8, gvali4, fixdms, gpnhri
c    datan,  write,  read,  dabs,  open,  stop
c
c    include files used:    n/a
c
c    common blocks used:    const, elipsoid
c
c    references:            see comments within subroutines
c
c    comments:
c
c********1*********2*********3*********4*********5*********6*********7**
c::modification history
c::1990mm.dd, sjf, creation of program       
c::199412.15, bmt, creation of program on viper
c::200203.08, crs, modified by c.schwarz to correct spelling of Clarke
c::200207.15, rws, modified i/o & standardized program documentation
c::                added subs trim, bufdms, gethem, gvali4, gvalr8   
c::200207.23, rws, replaced sub inver1 with gpnarc, gpnloa, gpnhri
c::200208.15, rws, fixed an error in bufdms
c::              - renamed ellips to elipss "common error" with dirct2
c::              - added FAZ & BAZ to printed output   
c::200208.19, rws, added more error flags for web interface code
c::              - added logical nowebb                         
c::200208.xx, sjf, program version number 2.0       
c********1*********2*********3*********4*********5*********6*********7**
ce::inverse
c
      implicit double precision (a-h, o-z)
      implicit integer (i-n)
c
      logical  nowebb
c
      character*1  answer,option,dmt,buff(50),hem
      character*6  d_ns1, d_ew1, d_ns2, d_ew2, d_mt
      character*30 filout,name1,name2,elips
c
      integer*4    ierror
      integer*4    lgh
c
      common/const/pi,rad
      common/elipsoid/a,f
c
c    ms_unix      0 = web version
c                  1 = ms_dos or unix version
c
      parameter  ( ms_unix = 0 )
c
      pi  = 4.d0*datan(1.d0)
      rad  = 180.d0/pi
      dmt  = 'm'
      d_mt = 'Meters'
c
      if( ms_unix.eq.1 )then
        nowebb = .true.
      else
        nowebb = .false.
      endif
c
    1 do 2 i=1,25
        write(*,*) '  '
    2 continue
c
    5 write(*,*) '  Program Inverse  -  Version 2.0 '
      write(*,*) '  '
      write(*,*) '  Ellipsoid options : '
      write(*,*) '  '
      write(*,*) '  1) GRS80 / WGS84  (NAD83) '
      write(*,*) '  2) Clarke 1866    (NAD27) '
      write(*,*) '  3) Any other ellipsoid '
      write(*,*) '  '
      write(*,*) '  Enter choice : '
      read(*,10) option
  10 format(a1)
c
      if(option.eq.'1') then
        a=6378137.d0
        f=1.d0/298.25722210088d0
        elips='GRS80 / WGS84  (NAD83)'
      elseif(option.eq.'2') then
        a=6378206.4d0
        f=1.d0/294.9786982138d0
        elips='Clarke 1866    (NAD27)'
      elseif(option.eq.'3') then
        call elipss (elips)
      else
        write(*,*) '  Enter 1, 2, or 3 !  Try again --'
        goto 5
      endif
c
      esq = f*(2.0d0-f)
c
      write(*,*) '  '
      write(*,*) '  '
      write(*,*) '  '
      write(*,*) '  '
c
  15 write(*,*) '  Enter First Station '
      write(*,16)
  16 format(18x,'(Separate D,M,S by blanks or commas)')
      write(*,*) 'hDD MM SS.sssss  Latitude :        (h default = N )'
  11 format(50a1)
c
  22 hem='N'
      read(*,11) buff
      call trim (buff,lgh,hem)
      call bufdms (buff,lgh,hem,dd,dm,ds,ierror)
c
      if( ierror.eq.0 )then
        irlat1 = 0
      else
        irlat1 = 1
        write(*,*) ' Invalid Latitude ... Please re-enter it '
        write(*,*) '  '
        if( nowebb )then
          goto 22
        endif
      endif
c
      ald1 = dd
      alm1 = dm
      sl1  = ds
c
      if( hem.eq.'N' ) then
        lat1sn = +1
      else
        lat1sn = -1
      endif
c
      write(*,*) 'hDDD MM SS.sssss Longitude :      (h default = W )'
c
  23 hem='W'
      read(*,11) buff
      call trim (buff,lgh,hem)
      call bufdms (buff,lgh,hem,dd,dm,ds,ierror)
c
      if( ierror.eq.0 )then
        irlon1 = 0
      else
        irlon1 = 1
        write(*,*) ' Invalid Longitude ... Please re-enter it '
        write(*,*) '  '
        if( nowebb )then
          goto 23
        endif
      endif
c
      alod1 = dd
      alom1 = dm
      slo1  = ds
c
      if( hem.eq.'E' ) then
        lon1sn = +1
      else
        lon1sn = -1
      endif
c
      call getrad(ald1, alm1, sl1, lat1sn, glat1)
      call getrad(alod1,alom1,slo1,lon1sn, glon1)
c
      write(*,*) '  '
      write(*,*) '  '
c
  20 write(*,*) '  Enter Second Station '
      write(*,16)
      write(*,*) 'hDD MM SS.sssss  Latitude :        (h default = N )'
c
  24 hem='N'
      read(*,11) buff
      call trim (buff,lgh,hem)
      call bufdms (buff,lgh,hem,dd,dm,ds,ierror)
c
      if( ierror.eq.0 )then
        irlat2 = 0
      else
        irlat2 = 1
        write(*,*) ' Invalid Latitude ... Please re-enter it '
        write(*,*) '  '
        if( nowebb )then
          goto 24
        endif
      endif
c
      ald2 = dd
      alm2 = dm
      sl2  = ds
c
      if( hem.eq.'N' ) then
        lat2sn = +1
      else
        lat2sn = -1
      endif
c
      write(*,*) 'hDDD MM SS.sssss Longitude :      (h default = W )'
c
  25 hem='W'
      read(*,11) buff
      call trim (buff,lgh,hem)
      call bufdms (buff,lgh,hem,dd,dm,ds,ierror)
c
      if( ierror.eq.0 )then
        irlon2 = 0
      else
        irlon2 = 1
        write(*,*) ' Invalid Longitude ... Please re-enter it '
        write(*,*) '  '
        if( nowebb )then
          goto 25
        endif
      endif
c
      alod2 = dd
      alom2 = dm
      slo2  = ds
c
      if( hem.eq.'E' )then
        lon2sn = +1
      else
        lon2sn = -1
      endif
c
      call getrad(ald2, alm2, sl2, lat2sn, glat2)
      call getrad(alod2,alom2,slo2,lon2sn, glon2)
c
      p1 = glat1
      e1 = glon1
      p2 = glat2
      e2 = glon2
c
      if( e1.lt.0.0d0 )then
        e1 = e1+2.0d0*pi
      endif
      if( e2.lt.0.0d0 )then
        e2 = e2+2.0d0*pi
      endif
c
c    compute the geodetic inverse
c
c ************************************************************
c *  replaced subroutine inver1 with gpnhri
c *
c *  call inver1 (glat1,glon1,glat2,glon2,faz,baz,edist)
c *
c ************************************************************
c
      call gpnhri (a,f,esq,pi,p1,e1,p2,e2,faz,baz,edist)
c
c    check for a non distance ... p1,e1 & p2,e2 equal zero ?
c
      if( edist.lt.0.00005d0 )then
        faz = 0.0d0
        baz = 0.0d0
      endif
c
c    set the tolerance (in seconds) for the azimuth conversion
c
      tol = 0.00005d0
c
      call todmsp(faz,iaz1,maz1,saz1,isign1)
      if(isign1.lt.0) then
        iaz1=359-iaz1
        maz1=59-maz1
        saz1=60.d0-saz1
      endif
      call fixdms ( iaz1, maz1, saz1, tol )
c
      call todmsp(baz,iaz2,maz2,saz2,isign2)
      if(isign2.lt.0) then
        iaz2=359-iaz2
        maz2=59-maz2
        saz2=60.d0-saz2
      endif
      call fixdms ( iaz2, maz2, saz2, tol )
c
      call todmsp(glat1, ld1,  lm1,  sl1,  lat1sn)
      call todmsp(glon1, lod1, lom1, slo1, lon1sn)
      call todmsp(glat2, ld2,  lm2,  sl2,  lat2sn)
      call todmsp(glon2, lod2, lom2, slo2, lon2sn)
c
      call hem_ns ( lat1sn, d_ns1 )
      call hem_ew ( lon1sn, d_ew1 )
      call hem_ns ( lat2sn, d_ns2 )
      call hem_ew ( lon2sn, d_ew2 )
c
      write(*,*) '  '
      write(*,*) '  '
      write(*,*) '  '
      write(*,*) '  '
      write(*,*) '  '
      write(*,49) elips
  49 format('  Ellipsoid : ',a30)
      finv=1.d0/f
      b=a*(1.d0-f)
      write(*,50) a,b,finv
  50 format('  Equatorial axis,    a  = ',f15.4,/,
    *      '  Polar axis,        b  = ',f15.4,/,
    *      '  Inverse flattening, 1/f = ',f16.11)
c
  18 format('    LAT = ',i3,1x,i2,1x,f8.5,1x,a6)
  19 format('    LON = ',i3,1x,i2,1x,f8.5,1x,a6)
c
      write(*,*) '  '
      write(*,*) '  First  Station : '
      write(*,*) '  ---------------- '
      write(*,18) ld1, lm1, sl1, d_ns1   
      write(*,19) lod1,lom1,slo1,d_ew1
c
      write(*,*) '  '
      write(*,*) '  Second Station : '
      write(*,*) '  ---------------- '
      write(*,18) ld2, lm2, sl2, d_ns2
      write(*,19) lod2,lom2,slo2,d_ew2
c
  32 format('  Ellipsoidal distance    S = ',f14.4,1x,a1)
  34 format('  Forward azimuth        FAZ = ',i3,1x,i2,1x,f7.4,
    1      ' From North')
  35 format('  Back azimuth          BAZ = ',i3,1x,i2,1x,f7.4,
    1      ' From North')
c
      write(*,*) '  '
      write(*,34) iaz1,maz1,saz1
      write(*,35) iaz2,maz2,saz2
      write(*,32) edist,dmt
      write(*,*) '  '
      write(*,*) '  Do you want to save this output into a file (y/n)?'
      read(*,10) answer
c
      if( answer.eq.'Y'.or.answer.eq.'y' )then
  39  write(*,*) '  Enter the output filename : '
        read(*,40) filout
  40  format(a30)
        open(3,file=filout,status='new',err=99)
        goto 98
c
  99  write(*,*) '  File already exists, try again.'
        go to 39
c
  98  continue
        write(3,*) '  '
        write(3,49) elips
        finv=1.d0/f
        b=a*(1.d0-f)
        write(3,50) a,b,finv
        write(*,*) '  Enter the First Station name : '
        read(*,40) name1
        write(*,*) '  Enter the Second Station name : '
        read(*,40) name2
c
  41  format('  First  Station : ',a30)
  42  format('  Second Station : ',a30)
  84  format('  Error: First  Station ... Invalid Latitude  ')
  85  format('  Error: First  Station ... Invalid Longitude ')
  86  format('  Error: Second Station ... Invalid Latitude  ')
  87  format('  Error: Second Station ... Invalid Longitude ')
  88  format(1x,65(1h*))
  91  format('        DD(0-89) MM(0-59) SS(0-59.999...)  ')
  92  format('        DDD(0-359) MM(0-59) SS(0-59.999...)  ')
c
        write(3,*) '  '
        write(3,41) name1
        write(3,*) '  ---------------- '
 
        if( irlat1.eq.0 )then
          write(3,18) ld1, lm1, sl1, d_ns1
        else
          write(3,88)
          write(3,84)
          write(3,91)                     
          write(3,88)
        endif
c
        if( irlon1.eq.0 )then   
          write(3,19) lod1,lom1,slo1,d_ew1
        else
          write(3,88)
          write(3,85)
          write(3,92)                   
          write(3,88)
        endif
c
        write(3,*) '  '
        write(3,42) name2
        write(3,*) '  ---------------- '
c
        if( irlat2.eq.0 )then
          write(3,18) ld2, lm2, sl2, d_ns2
        else
          write(3,88)
          write(3,86)
          write(3,91)                   
          write(3,88)
        endif
c
        if( irlon2.eq.0 )then
          write(3,19) lod2,lom2,slo2,d_ew2
        else
          write(3,88)
          write(3,87)
          write(3,92)                   
          write(3,88)
        endif
c
        write(3,*) '  '
        write(3,34) iaz1,maz1,saz1
        write(3,35) iaz2,maz2,saz2
        write(3,32) edist,dmt
        write(3,*) '  '
      endif
c
  80 write(*,*) '  '
      write(*,*) '  '
      write(*,*) '  '
      write(*,*) '  1) Another inverse, different ellipsoid.'
      write(*,*) '  2) Same ellipsoid, two new stations.'
      write(*,*) '  3) Same ellipsoid, same First Station.'
      write(*,*) '  4) Done.'
      write(*,*) '  '
      write(*,*) '  Enter choice : '
      read(*,10) answer
c
      if(    answer.eq.'1' )then
        goto 1
      elseif( answer.eq.'2' )then
        goto 15
      elseif( answer.eq.'3' )then
        goto 20
      else
        write(*,*) '  Thats all, folks!'
      endif
 
c    stop
      end
 
      subroutine bufdms (buff,lgh,hem,dd,dm,ds,ierror)
      implicit double precision (a-h, o-z)
      implicit integer (i-n)
c
      logical    done,flag
c
      character*1 buff(*),abuf(21)
      character*1 ch
      character*1 hem
      integer*4  ll,lgh
      integer*4  i4,id,im,is,icond,ierror
      real*8      x(5)
c
c    set the "error flag"
c
      ierror = 0
      icond  = 0
c
c    set defaults for dd,dm,ds
c
      dd = 0.0d0
      dm = 0.0d0
      ds = 0.0d0
c
c    set default limits for "hem" flag
c
      if(    hem.eq.'N' .or. hem.eq.'S' )then
        ddmax = 90.0d0
      elseif( hem.eq.'E' .or. hem.eq.'W' )then
        ddmax = 360.0d0
      elseif( hem.eq.'A' )then
        ddmax = 360.0d0
      elseif( hem.eq.'Z' )then
        ddmax = 180.0d0
      elseif( hem.eq.'*' )then
        ddmax  = 0.0d0
        ierror = 1
      else
        ddmax = 360.0d0
      endif
c
      do 1 i=1,5
        x(i) = 0.0d0
    1 continue
c
      icolon = 0
      ipoint = 0
      icount = 0
      flag  = .true.
      jlgh  = lgh
c
      do 2 i=1,jlgh
        if( buff(i).eq.':' )then
          icolon = icolon+1
        endif
        if( buff(i).eq.'.' )then
          ipoint = ipoint+1
          flag  = .false.
        endif
        if( flag )then
          icount = icount+1
        endif
    2 continue
c
      if( ipoint.eq.1 .and. icolon.eq.0 )then
c
c      load temp buffer
c
        do 3 i=1,jlgh
          abuf(i) = buff(i)
    3  continue
        abuf(jlgh+1) = '$'
        ll = jlgh
c
        call gvalr8 (abuf,ll,r8,icond)
c
        if( icount.ge.5 )then
c
c        value is a packed decimal of ==>  DDMMSS.sssss   
c
          ss = r8/10000.0d0
          id = idint( ss )
c
          r8 = r8-10000.0d0*dble(float(id))
          ss = r8/100.0d0
          im = idint( ss )
c
          r8 = r8-100.0d0*dble(float(im))
        else
c
c        value is a decimal of ==>  .xx  X.xxx  X.
c
          id = idint( r8 )
          r8 = (r8-id)*60.0d0
          im = idint( r8 )
          r8 = (r8-im)*60.0d0
        endif
c
c      account for rounding error
c
        is = idnint( r8*1.0d5 )
        if( is.ge.6000000 )then
          r8 = 0.0d0
          im = im+1
        endif
c
        if( im.ge.60 )then
          im = 0
          id = id+1
        endif
c
        dd = dble( float( id ) )
        dm = dble( float( im ) )
        ds = r8
      else
c
c      buff() value is a d,m,s of ==>  NN:NN:XX.xxx 
c
        k    = 0
        next = 1
        done = .false.
        ie  = jlgh
c
        do 100 j=1,5
          ib = next
          do 90 i=ib,ie
            ch  = buff(i)
            last = i
            if( i.eq.jlgh .or. ch.eq.':' )then
              if( i.eq.jlgh )then
                done = .true.
              endif
              if( ch.eq.':' )then
                last = i-1
              endif
              goto 91
            endif
  90    continue
          goto 98
c
  91    ipoint = 0
          ik    = 0
          do 92 i=next,last
            ik = ik+1
            ch = buff(i)
            if( ch.eq.'.' )then
              ipoint = ipoint+1
            endif
            abuf(ik) = buff(i)
  92    continue
          abuf(ik+1) = '$'
c
          ll = ik
          if( ipoint.eq.0 )then
            call gvali4 (abuf,ll,i4,icond)
            r8 = dble(float( i4 ))
          else
            call gvalr8 (abuf,ll,r8,icond)
          endif
c
          k    = k+1
          x(k) = r8
c
  98    if( done )then
            goto 101
          endif
c
          next = last
  99    next = next+1 
          if( buff(next).eq.':' )then
            goto 99
          endif
  100  continue
c
c      load dd,dm,ds
c
  101  if( k.ge.1 )then
          dd = x(1)
        endif
c
        if( k.ge.2 )then
          dm = x(2)
        endif
c
        if( k.ge.3 )then
          ds = x(3)
        endif
      endif
c
      if( dd.gt.ddmax  .or.
    1    dm.ge.60.0d0 .or.
    1    ds.ge.60.0d0 )then
        ierror = 1
        dd = 0.0d0
        dm = 0.0d0
        ds = 0.0d0
      endif
c
      if( icond.ne.0 )then
        ierror = 1
      endif
c
      return
      end
 
      subroutine elipss (elips)
      implicit double precision(a-h,o-z)
      character*1  answer
      character*30 elips
      common/elipsoid/a,f
      write(*,*) '  Other Ellipsoids.'
      write(*,*) '  -----------------'
      write(*,*) '  '
      write(*,*) '  A) Airy 1858'
      write(*,*) '  B) Airy Modified'
      write(*,*) '  C) Australian National'
      write(*,*) '  D) Bessel 1841'
      write(*,*) '  E) Clarke 1880'
      write(*,*) '  F) Everest 1830'
      write(*,*) '  G) Everest Modified'
      write(*,*) '  H) Fisher 1960'
      write(*,*) '  I) Fisher 1968'
      write(*,*) '  J) Hough 1956'
      write(*,*) '  K) International (Hayford)'
      write(*,*) '  L) Krassovsky 1938'
      write(*,*) '  M) NWL-9D (WGS 66)'
      write(*,*) '  N) South American 1969'
      write(*,*) '  O) Soviet Geod. System 1985'
      write(*,*) '  P) WGS 72'
      write(*,*) '  Q-Z) User defined.'
      write(*,*) '  '
      write(*,*) '  Enter choice : '
      read(*,10) answer
  10 format(a1)
c
      if(answer.eq.'A'.or.answer.eq.'a') then
        a=6377563.396d0
        f=1.d0/299.3249646d0
        elips='Airy 1858'
      elseif(answer.eq.'B'.or.answer.eq.'b') then
        a=6377340.189d0
        f=1.d0/299.3249646d0
        elips='Airy Modified'
      elseif(answer.eq.'C'.or.answer.eq.'c') then
        a=6378160.d0
        f=1.d0/298.25d0
        elips='Australian National'
      elseif(answer.eq.'D'.or.answer.eq.'d') then
        a=6377397.155d0
        f=1.d0/299.1528128d0
        elips='Bessel 1841'
      elseif(answer.eq.'E'.or.answer.eq.'e') then
        a=6378249.145d0
        f=1.d0/293.465d0
        elips='Clarke 1880'
      elseif(answer.eq.'F'.or.answer.eq.'f') then
        a=6377276.345d0
        f=1.d0/300.8017d0
        elips='Everest 1830'
      elseif(answer.eq.'G'.or.answer.eq.'g') then
        a=6377304.063d0
        f=1.d0/300.8017d0
        elips='Everest Modified'
      elseif(answer.eq.'H'.or.answer.eq.'h') then
        a=6378166.d0
        f=1.d0/298.3d0
        elips='Fisher 1960'
      elseif(answer.eq.'I'.or.answer.eq.'i') then
        a=6378150.d0
        f=1.d0/298.3d0
        elips='Fisher 1968'
      elseif(answer.eq.'J'.or.answer.eq.'j') then
        a=6378270.d0
        f=1.d0/297.d0
        elips='Hough 1956'
      elseif(answer.eq.'K'.or.answer.eq.'k') then
        a=6378388.d0
        f=1.d0/297.d0
        elips='International (Hayford)'
      elseif(answer.eq.'L'.or.answer.eq.'l') then
        a=6378245.d0
        f=1.d0/298.3d0
        elips='Krassovsky 1938'
      elseif(answer.eq.'M'.or.answer.eq.'m') then
        a=6378145.d0
        f=1.d0/298.25d0
        elips='NWL-9D  (WGS 66)'
      elseif(answer.eq.'N'.or.answer.eq.'n') then
        a=6378160.d0
        f=1.d0/298.25d0
        elips='South American 1969'
      elseif(answer.eq.'O'.or.answer.eq.'o') then
        a=6378136.d0
        f=1.d0/298.257d0
        elips='Soviet Geod. System 1985'
      elseif(answer.eq.'P'.or.answer.eq.'p') then
        a=6378135.d0
        f=1.d0/298.26d0
        elips='WGS 72'
      else
        elips = 'User defined.'
c
        write(*,*) '  Enter Equatorial axis,  a : '
        read(*,*) a
        a  = dabs(a)
c
        write(*,*) '  Enter either Polar axis, b or '
        write(*,*) '  Reciprocal flattening,  1/f : '
        read(*,*) ss
        ss = dabs(ss)
c
        f = 0.0d0
        if( 200.0d0.le.ss .and. ss.le.310.0d0 )then
          f = 1.d0/ss
        elseif( 6000000.0d0.lt.ss .and. ss.lt.a )then
          f = (a-ss)/a
        else
          elips = 'Error: default GRS80 used.'
          a    = 6378137.0d0
          f    = 1.0d0/298.25722210088d0
        endif
      endif
c
      return
      end
 
      subroutine fixdms (ideg, min, sec, tol )
c
      implicit double precision (a-h, o-z)
      implicit integer (i-n)
c
c    test for seconds near 60.0-tol
c
      if( sec.ge.( 60.0d0-tol ) )then
        sec  = 0.0d0
        min  = min+1
      endif
c
c    test for minutes near 60
c
      if( min.ge.60 )then
        min  = 0
        ideg = ideg+1
      endif
c
c    test for degrees near 360
c
      if( ideg.ge.360 )then
        ideg = 0
      endif
c
      return
      end
 
      subroutine hem_ns ( lat_sn, hem )
      implicit integer (i-n)
      character*6  hem
c
      if( lat_sn.eq.1 ) then
        hem = 'North '
      else
        hem = 'South '
      endif
c
      return
      end
      subroutine hem_ew ( lon_sn, hem )
      implicit integer (i-n)
      character*6  hem
c
      if( lon_sn.eq.1 ) then
        hem = 'East  '
      else
        hem = 'West  '
      endif
c
      return
      end
      subroutine getrad(d,m,sec,isign,val)
 
*** comvert deg, min, sec to radians
 
      implicit double precision(a-h,j-z)
      common/const/pi,rad
 
      val=(d+m/60.d0+sec/3600.d0)/rad
      val=dble(isign)*val
 
      return
      end
 
CB::GPNARC
C
      SUBROUTINE GPNARC (AMAX,FLAT,ESQ,PI,P1,P2,ARC)
C
C********1*********2*********3*********4*********5*********6*********7*
C
C NAME:        GPNARC
C VERSION:    200005.26
C WRITTEN BY:  ROBERT (Sid) SAFFORD
C PURPOSE:    SUBROUTINE TO COMPUTE THE LENGTH OF A MERIDIONAL ARC
C              BETWEEN TWO LATITUDES
C
C INPUT PARAMETERS:
C -----------------
C AMAX        SEMI-MAJOR AXIS OF REFERENCE ELLIPSOID
C FLAT        FLATTENING (0.0033528 ... )
C ESQ          ECCENTRICITY SQUARED FOR REFERENCE ELLIPSOID
C PI          3.14159...
C P1          LAT STATION 1
C P2          LAT STATION 2
C
C OUTPUT PARAMETERS:
C ------------------
C ARC          GEODETIC DISTANCE
C
C LOCAL VARIABLES AND CONSTANTS:
C ------------------------------
C GLOBAL VARIABLES AND CONSTANTS:
C -------------------------------
C
C    MODULE CALLED BY:    GENERAL
C
C    THIS MODULE CALLS:
C      LLIBFORE/ OPEN,  CLOSE,  READ,  WRITE,  INQUIRE
C                DABS,  DBLE,  FLOAT,  IABS,  CHAR,  ICHAR
C
C    INCLUDE FILES USED:
C    COMMON BLOCKS USED:
C
C    REFERENCES: Microsoft FORTRAN 4.10 Optimizing Compiler, 1988
C                MS-DOS Operating System
C    COMMENTS:
C********1*********2*********3*********4*********5*********6*********7*
C::MODIFICATION HISTORY
C::197507.05, RWS, VER 00 TENCOL RELEASED FOR FIELD USE
C::198311.20, RWS, VER 01 MTEN  RELEASED TO FIELD
C::198411.26, RWS, VER 07 MTEN2  RELEASED TO FIELD
C::1985xx.xx, RWS, CODE  CREATED           
C::198506.10, RWS, WRK    ENHANCEMENTS RELEASED TO FIELD
C::198509.01, RWS, VER 11 MTEN3  RELEASED TO FIELD
C::198512.18, RWS, CODE  MODIFIED FOR MTEN3
C::198708.10, RWS, CODE  MODIFIED TO USE NEW MTEN4 GPN RECORD FORMAT
C::199112.31, RWS, VER 20 MTEN4 RELEASED TO FIELD
C::200001.13, RWS, VER 21 MTEN4 RELEASED TO FIELD
C::200005.26, RWS, CODE  RESTRUCTURED & DOCUMENTATION ADDED         
C::200012.31, RWS, VER 23 MTEN5 RELEASED                             
C********1*********2*********3*********4*********5*********6*********7*
CE::GPNARC
C ---------------------------
C    M T E N  (VERSION 3)
C    M T E N  (VERSION 5.23)
C ---------------------------
C
      IMPLICIT REAL*8 (A-H,O-Z)
C
      LOGICAL  FLAG
C
      DATA TT/5.0D-15/
C
C    CHECK FOR A 90 DEGREE LOOKUP
C
      FLAG = .FALSE.
C
      S1 = DABS(P1)
      S2 = DABS(P2)
C
      IF( (PI/2.0D0-TT).LT.S2 .AND. S2.LT.(PI/2.0D0+TT) )THEN
        FLAG = .TRUE.
      ENDIF
C
      IF( S1.GT.TT )THEN
        FLAG = .FALSE.
      ENDIF
C
      DA = (P2-P1)
      S1 = 0.0D0
      S2 = 0.0D0
C
C    COMPUTE THE LENGTH OF A MERIDIONAL ARC BETWEEN TWO LATITUDES
C
      E2 = ESQ
      E4 = E2*E2
      E6 = E4*E2
      E8 = E6*E2
      EX = E8*E2
C
      T1 = E2*(003.0D0/4.0D0)
      T2 = E4*(015.0D0/64.0D0)
      T3 = E6*(035.0D0/512.0D0)
      T4 = E8*(315.0D0/16384.0D0)
      T5 = EX*(693.0D0/131072.0D0)
C
      A  = 1.0D0+T1+3.0D0*T2+10.0D0*T3+35.0D0*T4+126.0D0*T5
C
      IF( FLAG )THEN
        GOTO 1
      ENDIF
C
      B  = T1+4.0D0*T2+15.0D0*T3+56.0D0*T4+210.0D0*T5
      C  = T2+06.0D0*T3+28.0D0*T4+120.0D0*T5
      D  = T3+08.0D0*T4+045.0D0*T5
      E  = T4+010.0D0*T5
      F  = T5
C
      DB = DSIN(P2*2.0D0)-DSIN(P1*2.0D0)
      DC = DSIN(P2*4.0D0)-DSIN(P1*4.0D0)
      DD = DSIN(P2*6.0D0)-DSIN(P1*6.0D0)
      DE = DSIN(P2*8.0D0)-DSIN(P1*8.0D0)
      DF = DSIN(P2*10.0D0)-DSIN(P1*10.0D0)
C
C    COMPUTE THE S2 PART OF THE SERIES EXPANSION
C
      S2 = -DB*B/2.0D0+DC*C/4.0D0-DD*D/6.0D0+DE*E/8.0D0-DF*F/10.0D0
C
C    COMPUTE THE S1 PART OF THE SERIES EXPANSION
C
    1 S1 = DA*A
C
C    COMPUTE THE ARC LENGTH
C
      ARC = AMAX*(1.0D0-ESQ)*(S1+S2)
C
      RETURN
      END
cb::gpnhri
c
      subroutine gpnhri (a,f,esq,pi,p1,e1,p2,e2,az1,az2,s)   
c
c********1*********2*********3*********4*********5*********6*********7*
c
c name:        gpnhri
c version:    200208.09
c written by:  robert (sid) safford
c purpose:    subroutine to compute helmert rainsford inverse problem
c
c    solution of the geodetic inverse problem after t. vincenty
c    modified rainsford's method with helmert's elliptical terms
c    effective in any azimuth and at any distance short of antipocal
c    from/to stations must not be the geographic pole.
c    parameter a is the semi-major axis of the reference ellipsoid
c    finv=1/f is the inverse flattening of the reference ellipsoid
c    latitudes and longitudes in radians positive north and west
c    forward and back azimuths returned in radians clockwise from south
c    geodesic distance s returned in units of semi-major axis a
c    programmed for ibm 360-195  09/23/75
c
c    note - note - note -
c    1. do not use for meridional arcs and be careful on the equator.
c    2. azimuths are from north(+) clockwise and
c    3. longitudes are positive east(+)
c
c input parameters:
c -----------------
c a            semi-major axis of reference ellipsoid      meters
c f            flattening (0.0033528...)
c esq          eccentricity squared
c pi          3.14159...
c p1          lat station 1                              radians
c e1          lon station 1                              radians
c p2          lat station 2                              radians
c e2          lon station 2                              radians
c
c output parameters:
c ------------------
c az1          azi at sta 1 -> sta 2                      radians
c az2          azi at sta 2 -> sta 1                      radians
c s            geodetic dist between sta(s) 1 & 2          meters
c
c local variables and constants:
c ------------------------------
c aa              constant from subroutine gpnloa                 
c alimit          equatorial arc distance along the equator  (radians)
c arc              meridional arc distance latitude p1 to p2 (in meters)   
c az1              azimuth forward                          (in radians)
c az2              azimuth back                            (in radians)
c bb              constant from subroutine gpnloa                 
c dlon            temporary value for difference in longitude (radians)
c equ              equatorial distance                      (in meters)
c r1,r2            temporary variables 
c s                ellipsoid distance                        (in meters)
c sms              equatorial - geodesic distance (S - s) "Sms"   
c ss              temporary variable 
c tol0            tolerance for checking computation value     
c tol1            tolerance for checking a real zero value     
c tol2            tolerance for close to zero value
c twopi            two times constant pi           
c
c global variables and constants:
c -------------------------------
c
c    module called by:    general
c
c    this module calls:  gpnarc, gpnloa
c      llibfore/ dsin,  dcos,  dsqrt,  dabs,  datan2, write
c
c    include files used:
c    common blocks used:
c
c    references: microsoft fortran 4.10 optimizing compiler, 1988
c                ms-dos operating system
c    comments:
c********1*********2*********3*********4*********5*********6*********7*
c::modification history
c::197507.05, rws, ver 00 tencol released for field use
c::198311.20, rws, ver 01 mten  released to field
c::198411.26, rws, ver 07 mten2  released to field
c::198506.10, rws, wrk    enhancements released to field
c::198507.22, rws, code  modified for mten3
c::198509.01, rws, ver 11 mten3  released to field
c::198708.10, rws, code  modified to use new mten4 gpn record format
c::199112.31, rws, ver 20 mten4 released to field
c::200001.13, rws, ver 21 mten4 released to field
c::200005.26, rws, code  restructured & documentation added         
c::200012.31, rws, ver 23 mten5 released                             
c::200104.09, rws, code  added to calblin program                   
c::200208.09, rws, code  added subroutines gpnarc & gpnloa           
c********1*********2*********3*********4*********5*********6*********7*
ce::gpnhri
c  -------------------------------
c    m t e n  (version 3)
c              (version 4.22)
c              (version 5.23)
c  -------------------------------
c
      implicit real*8 (a-h,o-z)
c
      data tol0 /5.0d-15/
      data tol1 /5.0d-14/
      data tol2 /7.0d-03/
c
      twopi = 2.0d0*pi
c
c    test the longitude difference with tol1
c    tol1 is approximately 0.000000001 arc seconds
c
      ss = e2-e1
      if( dabs(ss).lt.tol1 )then
        e2 = e2+tol1
        write(*,*) ' longitudal difference is near zero '
c             
        r2 = p2
        r1 = p1
        call gpnarc ( a, f, esq, pi, r1, r2, arc )
        s  = dabs( arc )
c
        if( p2.gt.p1 )then
          az1 = 0.0d0
          az2 = pi
        else
          az1 = pi
          az2 = 0.0d0
        endif
        return
      endif
c
c    test for longitude over 180 degrees
c
      dlon = e2-e1
c
      if( dlon.ge.0.0d0 )then
        if( pi.le.dlon .and. dlon.lt.twopi )then
          dlon = dlon-twopi
        endif
      else
        ss = dabs(dlon)
        if( pi.le.ss .and. ss.lt.twopi )then
          dlon = dlon+twopi
        endif
      endif
c
      ss = dabs( dlon )
      if( ss.gt.pi )then
c::    write(*,*) '  '
c::    write(*,*) ' Longitude difference over 180 degrees  '
c::    write(*,*) ' Turn it around '
        ss = twopi-ss
      endif
c
c    compute the limit in longitude (alimit), it is equal
c    to twice the distance from the equator to the pole,
c    as measured along the equator (east/ewst)
c
      alimit = pi*(1.0d0-f)
c
c    test for anti-nodal difference   
c
      if( ss.ge.alimit )then
        r1 = dabs(p1)
        r2 = dabs(p2)
c
c      latitudes r1 & r2 are not near the equator
c
        if( r1.gt.tol2 .and. r2.gt.tol2 )then
          goto 60
        endif
c
c      longitude difference is greater than lift-off point
c      now check to see if  "both"  r1 & r2 are on equator
c
        if( r1.lt.tol1 .and. r2.gt.tol2 )then
          goto 60
        endif
        if( r2.lt.tol1 .and. r1.gt.tol2 )then
          goto 60
        endif
c
c      check for either r1 or r2 just off the equator but < tol2
c
        if( r1.gt.tol1. or. r2.gt.tol1 )then
          az1 = 0.0d0
          az2 = 0.0d0
          s  = 0.0d0
          return
        endif
c
c      compute the azimuth to anti-nodal point
c
c::    write(*,*) '  '
c::    write(*,*) ' Longitude difference beyond lift-off point '
c::    write(*,*) '  '
c
        call gpnloa (a,f,esq,pi,dlon,az1,az2,aa,bb,sms)
c
c      compute the equatorial distance & geodetic
c
        equ = a*dabs(dlon)
        s  = equ-sms
        return
      endif
c
  60 continue
c
      f0  = (1.0d0-f)
      b    = a*f0
      epsq = esq/(1.0d0-esq)
      f2  = f*f 
      f3  = f*f2 
      f4  = f*f3 
c
c    the longitude difference
c
      dlon  = e2-e1
      ab    = dlon   
      kount = 0 
c
c    the reduced latitudes 
c
      u1    = f0*dsin(p1)/dcos(p1) 
      u2    = f0*dsin(p2)/dcos(p2)
c
      u1    = datan(u1)
      u2    = datan(u2)
c
      su1  = dsin(u1) 
      cu1  = dcos(u1) 
c
      su2  = dsin(u2)
      cu2  = dcos(u2)
c
c    counter for the iteration operation
c
    1 kount = kount+1 
c
      clon  = dcos(ab)
      slon  = dsin(ab)
c
      csig  = su1*su2+cu1*cu2*clon
      ssig  = dsqrt((slon*cu2)**2+(su2*cu1-su1*cu2*clon)**2)
c
      sig  = datan2(ssig,csig)
      sinalf=cu1*cu2*slon/ssig
c
      w  = (1.0d0-sinalf*sinalf)
      t4  = w*w
      t6  = w*t4
c
c    the coefficients of type a   
c
      ao  = f-f2*(1.0d0+f+f2)*w/4.0d0+3.0d0*f3*(1.0d0+
    1        9.0d0*f/4.0d0)*t4/16.0d0-25.0d0*f4*t6/128.0d0
      a2  = f2*(1.0d0+f+f2)*w/4.0d0-f3*(1.0d0+9.0d0*f/4.0d0)*t4/4.0d0+
    1        75.0d0*f4*t6/256.0d0
      a4  = f3*(1.0d0+9.0d0*f/4.0d0)*t4/32.0d0-15.0d0*f4*t6/256.0d0
      a6  = 5.0d0*f4*t6/768.0d0
c
c    the multiple angle functions 
c
      qo  = 0.0d0
      if( w.gt.tol0 )then
        qo = -2.0d0*su1*su2/w
      endif 
c
      q2  = csig+qo
      q4  = 2.0d0*q2*q2-1.0d0 
      q6  = q2*(4.0d0*q2*q2-3.0d0)   
      r2  = 2.0d0*ssig*csig   
      r3  = ssig*(3.0d0-4.0d0*ssig*ssig)
c
c    the longitude difference
c
      s  = sinalf*(ao*sig+a2*ssig*q2+a4*r2*q4+a6*r3*q6) 
      xz  = dlon+s
c
      xy  = dabs(xz-ab) 
      ab  = dlon+s
c
      if( xy.lt.0.5d-13 )then
        goto 4
      endif
c
      if( kount.le.7 )then
        goto 1
      endif
c
c    the coefficients of type b   
c
    4 z  = epsq*w
c
      bo  = 1.0d0+z*(1.0d0/4.0d0+z*(-3.0d0/64.0d0+z*(5.0d0/256.0d0-
    1        z*175.0d0/16384.0d0)))   
      b2  = z*(-1.0d0/4.0d0+z*(1.0d0/16.0d0+z*(-15.0d0/512.0d0+
    1        z*35.0d0/2048.0d0)))
      b4  = z*z*(-1.0d0/128.0d0+z*(3.0d0/512.0d0-z*35.0d0/8192.0d0))
      b6  = z*z*z*(-1.0d0/1536.0d0+z*5.0d0/6144.0d0) 
c
c    the distance in meters
c
      s  = b*(bo*sig+b2*ssig*q2+b4*r2*q4+b6*r3*q6)
c
c    first compute the az1 & az2 for along the equator
c
      if( dlon.gt.pi )then
        dlon = (dlon-2.0d0*pi)
      endif
c
      if( dabs(dlon).gt.pi )then
        dlon = (dlon+2.0d0*pi)
      endif
c
      az1 = pi/2.0d0
      if( dlon.lt.0.0d0 )then
        az1 = 3.0d0*az1
      endif
c
      az2 = az1+pi
      if( az2.gt.2.0d0*pi )then
        az2 = az2-2.0d0*pi
      endif
c
c    now compute the az1 & az2 for latitudes not on the equator
c
      if( .not.(dabs(su1).lt.tol0 .and. dabs(su2).lt.tol0) )then
        tana1 =  slon*cu2/(su2*cu1-clon*su1*cu2)
        tana2 =  slon*cu1/(su1*cu2-clon*su2*cu1)
        sina1 =  sinalf/cu1
        sina2 = -sinalf/cu2   
c
c      azimuths from north,longitudes positive east
c
        az1  = datan2(sina1,sina1/tana1)
        az2  = pi-datan2(sina2,sina2/tana2)
      endif
c
      if( az1.lt.0.0d0 )then
        az1 = az1+2.0d0*pi
      endif
c
      if( az2.lt.0.0d0 )then
        az2 = az2+2.0d0*pi
      endif
c
      return 
      end
 
CB::GPNLOA
C
      SUBROUTINE GPNLOA (AMAX,FLAT,ESQ,PI,DL,AZ1,AZ2,AO,BO,SMS)
C
C********1*********2*********3*********4*********5*********6*********7*
C
C NAME:        GPNLOA
C VERSION:    200005.26
C WRITTEN BY:  ROBERT (Sid) SAFFORD
C PURPOSE:    SUBROUTINE TO COMPUTE THE LIFF-OFF-AZIMUTH CONSTANTS
C
C INPUT PARAMETERS:
C -----------------
C AMAX        SEMI-MAJOR AXIS OF REFERENCE ELLIPSOID
C FLAT        FLATTENING (0.0033528 ... )
C ESQ          ECCENTRICITY SQUARED FOR REFERENCE ELLIPSOID
C PI          3.14159...
C DL          LON DIFFERENCE
C AZ1          AZI AT STA 1 -> STA 2
C
C OUTPUT PARAMETERS:
C ------------------
C AZ2          AZ2 AT STA 2 -> STA 1
C AO          CONST
C BO          CONST
C SMS          DISTANCE ... EQUATORIAL - GEODESIC  (S - s)  "SMS"
C
C LOCAL VARIABLES AND CONSTANTS:
C ------------------------------
C GLOBAL VARIABLES AND CONSTANTS:
C -------------------------------
C
C    MODULE CALLED BY:    GENERAL
C
C    THIS MODULE CALLS:
C      LLIBFORE/ DSIN,  DCOS,  DABS,  DASIN
C
C    INCLUDE FILES USED:
C    COMMON BLOCKS USED:
C
C    REFERENCES: Microsoft FORTRAN 4.10 Optimizing Compiler, 1988
C                MS-DOS Operating System
C    COMMENTS:
C********1*********2*********3*********4*********5*********6*********7*
C::MODIFICATION HISTORY
C::1985xx.xx, RWS, CODE  CREATED           
C::198506.10, RWS, WRK    ENHANCEMENTS RELEASED TO FIELD
C::198509.01, RWS, VER 11 MTEN3  RELEASED TO FIELD
C::198512.18, RWS, CODE  MODIFIED FOR MTEN3
C::198708.10, RWS, CODE  MODIFIED TO USE NEW MTEN4 GPN RECORD FORMAT
C::199112.31, RWS, VER 20 MTEN4 RELEASED TO FIELD
C::200001.13, RWS, VER 21 MTEN4 RELEASED TO FIELD
C::200005.26, RWS, CODE  RESTRUCTURED & DOCUMENTATION ADDED         
C::200012.31, RWS, VER 23 MTEN5 RELEASED                             
C********1*********2*********3*********4*********5*********6*********7*
CE::GPNLOA
C ---------------------------
C    M T E N  (VERSION 3)
C              (VERSION 4.22)
C              (VERSION 5.23)
C ---------------------------
C
      IMPLICIT REAL*8 (A-H,O-Z)
C
      DATA TT/5.0D-13/
C
      DLON = DABS(DL)
      CONS = (PI-DLON)/(PI*FLAT)
      F    = FLAT
C
C    COMPUTE AN APPROXIMATE AZ
C
      AZ  = DASIN(CONS)
C
      T1  =    1.0D0
      T2  =  (-1.0D0/4.0D0)*F*(1.0D0+F+F*F)
      T4  =    3.0D0/16.0D0*F*F*(1.0D0+(9.0D0/4.0D0)*F)
      T6  = (-25.0D0/128.0D0)*F*F*F
C
      ITER = 0
    1 ITER = ITER+1
      S    = DCOS(AZ)
      C2  = S*S
C
C    COMPUTE NEW AO
C
      AO  = T1 + T2*C2 + T4*C2*C2 + T6*C2*C2*C2
      CS  = CONS/AO
      S    = DASIN(CS)
      IF( DABS(S-AZ).LT.TT )THEN
        GOTO 2
      ENDIF
C
      AZ  = S
      IF( ITER.LE.6 )THEN
        GOTO 1
      ENDIF
C
    2 AZ1  = S
      IF( DL.LT.0.0D0 )THEN
        AZ1 = 2.0D0*PI-AZ1
      ENDIF
C
      AZ2  = 2.0D0*PI-AZ1
C
C    EQUATORIAL - GEODESIC  (S - s)  "SMS"
C
      ESQP = ESQ/(1.0D0-ESQ)
      S    = DCOS(AZ1)
C
      U2  = ESQP*S*S
      U4  = U2*U2
      U6  = U4*U2
      U8  = U6*U2
C
      T1  =    1.0D0
      T2  =    (1.0D0/4.0D0)*U2
      T4  =  (-3.0D0/64.0D0)*U4
      T6  =    (5.0D0/256.0D0)*U6
      T8  = (-175.0D0/16384.0D0)*U8
C
      BO  = T1 + T2 + T4 + T6 + T8
      S    = DSIN(AZ1)
      SMS  = AMAX*PI*(1.0D0 - FLAT*DABS(S)*AO - BO*(1.0D0-FLAT))
C
      RETURN
      END
      subroutine gvali4 (buff,ll,vali4,icond)
      implicit    integer (i-n)
c
      logical      plus,sign,done,error
      character*1  buff(*)
      character*1  ch
c
c    integer*2    i
c    integer*2    l1
c
      integer*4    ich,icond
      integer*4    ll 
      integer*4    vali4
c
      l1    = ll
      vali4 = 0
      icond = 0
      plus  = .true.
      sign  = .false.
      done  = .false.
      error = .false.
c
      i = 0
  10 i = i+1
      if( i.gt.l1 .or. done )then
        go to 1000
      else
        ch  = buff(i)
        ich = ichar( buff(i) )
      endif
c
      if(    ch.eq.'+' )then
c
c      enter on plus sign
c
        if( sign )then
          goto 150
        else
          sign = .true.
          goto 10
        endif
      elseif( ch.eq.'-' )then
c
c      enter on minus sign
c
        if( sign )then
          goto 150
        else
          sign = .true.
          plus = .false.
          goto 10
        endif
      elseif( ch.ge.'0' .and. ch.le.'9' )then
        goto 100
      elseif( ch.eq.' ' )then
c
c      enter on space -- ignore leading spaces
c
        if( .not.sign )then
          goto 10
        else
          buff(i) = '0'
          ich = 48
          goto 100
        endif
      elseif( ch.eq.':' )then
c
c      enter on colon -- ignore
c
        if( .not.sign )then
          goto 10
        else
          goto 1000
        endif
      elseif( ch.eq.'$' )then
c
c      enter on dollar "$"   
c
        done = .true.
        goto 10
      else
c
c      something wrong
c
        goto 150
      endif
c
c    enter on numeric
c
  100 vali4 = 10*vali4+(ich-48)
      sign  = .true.
      goto 10
c
c    treat illegal character
c
  150 buff(i) = '0'
      vali4 = 0
      icond = 1
c
1000 if( .not.plus )then
        vali4 = -vali4
      endif
c
      return
      end
      subroutine gvalr8 (buff,ll,valr8,icond)
      implicit    integer (i-n)
c
      logical      plus,sign,dpoint,done
c
      character*1  buff(*)
      character*1  ch
c
c    integer*2    i, ip
c    integer*2    l1
c    integer*2    nn, num, n48
c
      integer*4    ich,icond
      integer*4    ll
c
      real*8      ten
      real*8      valr8
      real*8      zero
c
      data zero,ten/0.0d0,10.0d0/
c
      n48    =  48
      l1      =  ll
      icond  =  0
      valr8  =  zero
      plus    = .true.
      sign    = .false.
      dpoint  = .false.
      done    = .false.
c
c    start loop thru buffer
c
      i = 0
  10 i = i+1
      if( i.gt.l1 .or. done )then
        go to 1000
      else
        ch  = buff(i)
        nn  = ichar( ch )
        ich = nn
      endif
c
      if(    ch.eq.'+' )then
c
c      enter on plus sign
c
        if( sign )then
          goto 150
        else
          sign = .true.
          goto 10
        endif
      elseif( ch.eq.'-' )then
c
c      enter on minus sign
c
        if( sign )then
          goto 150
        else
          sign = .true.
          plus = .false.
          goto 10
        endif
      elseif( ch.eq.'.' )then
c
c      enter on decimal point
c
        ip    = 0
        sign  = .true.
        dpoint = .true.
        goto 10
      elseif( ch.ge.'0' .and. ch.le.'9' )then
        goto 100
      elseif( ch.eq.' ' )then
c
c      enter on space
c
        if( .not.sign )then
          goto 10
        else
          buff(i) = '0'
          ich = 48
          goto 100
        endif
      elseif( ch.eq.':' .or. ch.eq.'$' )then
c
c      enter on colon or "$" sign
c
        done = .true.
        goto 10
      else
c
c      something wrong
c
        goto 150
      endif
c
c    enter on numeric
c
  100 sign = .true.
      if( dpoint )then
        ip = ip+1
      endif
c
      num  = ich
      valr8 = ten*valr8+dble(float( num-n48 ))
      goto 10
c
c    treat illegal character
c
  150 buff(i) = '0'
      valr8  =  0.0d0
      icond  =  1
c
1000 if( dpoint )then
        valr8 =  valr8/(ten**ip)
      endif
c
      if( .not.plus )then
        valr8 = -valr8
      endif
c
      return
      end
 
      subroutine todmsp(val,id,im,s,isign)
 
*** convert position radians to deg,min,sec
*** range is [-pi to +pi]
 
      implicit double precision(a-h,o-z)
      common/const/pi,rad
 
    1 if(val.gt.pi) then
        val=val-pi-pi
        go to 1
      endif
 
    2 if(val.lt.-pi) then
        val=val+pi+pi
        go to 2
      endif
 
      if(val.lt.0.d0) then
        isign=-1
      else
        isign=+1
      endif
 
      s=dabs(val*rad)
      id=idint(s)
      s=(s-id)*60.d0
      im=idint(s)
      s=(s-im)*60.d0
 
*** account for rounding error
 
      is=idnint(s*1.d5)
      if(is.ge.6000000) then
        s=0.d0
        im=im+1
      endif
      if(im.ge.60) then
        im=0
        id=id+1
      endif
 
      return
      end
 
      subroutine trim (buff,lgh,hem)
c
      implicit integer (i-n)
      character*1 ch,hem
      character*1 buff(*)
      integer*4  lgh
c
      ibeg = 1
      do 10 i=1,50
        if( buff(i).ne.' ' )then
          goto 11
        endif
        ibeg = ibeg+1
  10 continue
  11 continue
      if( ibeg.ge.50 )then
        ibeg = 1
        buff(ibeg) = '0'
      endif
c
      iend = 50
      do 20 i=1,50
        j = 51-i
        if( buff(j).eq.' ' )then
          iend = iend-1
        else
          goto 21
        endif
  20 continue
  21 continue
c
      ch = buff(ibeg)
      if( hem.eq.'N' )then
        if( ch.eq.'N' .or. ch.eq.'n' .or. ch.eq.'+' )then
          hem = 'N'
          ibeg = ibeg+1
        endif
        if( ch.eq.'S' .or. ch.eq.'s' .or. ch.eq.'-' )then
          hem = 'S'
          ibeg = ibeg+1
        endif
c
c      check for wrong hemisphere entry
c
        if( ch.eq.'E' .or. ch.eq.'e' )then
          hem = '*'
          ibeg = ibeg+1
        endif
        if( ch.eq.'W' .or. ch.eq.'w' )then
          hem = '*'
          ibeg = ibeg+1
        endif
      elseif( hem.eq.'W' )then
        if( ch.eq.'E' .or. ch.eq.'e' .or. ch.eq.'+' )then
          hem = 'E'
          ibeg = ibeg+1
        endif
        if( ch.eq.'W' .or. ch.eq.'w' .or. ch.eq.'-' )then
          hem = 'W'
          ibeg = ibeg+1
        endif
c
c      check for wrong hemisphere entry
c
        if( ch.eq.'N' .or. ch.eq.'n' )then
          hem = '*'
          ibeg = ibeg+1
        endif
        if( ch.eq.'S' .or. ch.eq.'s' )then
          hem = '*'
          ibeg = ibeg+1
        endif
      elseif( hem.eq.'A' )then
        if( .not.('0'.le.ch .and. ch.le.'9') )then
          hem = '*'
          ibeg = ibeg+1
        endif
      else
c        do nothing
      endif
c
c
      do 30 i=ibeg,iend
        ch = buff(i)
c
        if(    ch.eq.':' .or. ch.eq.'.' )then
          goto 30
        elseif( ch.eq.' ' .or. ch.eq.',' )then
          buff(i) = ':'
        elseif( '0'.le.ch .and. ch.le.'9' )then
          goto 30   
        else
          buff(i) = ':'
        endif
c
  30 continue
c
c    left justify buff() array to its first character position
c    also check for a ":" char in the starting position,
c    if found!!  skip it
c
      j  = 0
      ib = ibeg
      ie = iend
c
      do 40 i=ib,ie
        if( i.eq.ibeg .and. buff(i).eq.':' )then
c
c        move the 1st position pointer to the next char &
c        do not put ":" char in buff(j) array where j=1 
c
          ibeg = ibeg+1
          goto 40
        endif
        j = j+1
        buff(j) = buff(i)
  40 continue
c
c
      lgh = iend-ibeg+1
      j  = lgh+1
      buff(j) = '$'
c
c    clean-up the rest of the buff() array
c
      do 50 i=j+1,50
        buff(i) = ' ' 
  50 continue
c
c    save a maximum of 20 characters
c
      if( lgh.gt.20 )then
        lgh = 20
        j  = lgh+1
        buff(j) = '$'
      endif
c
      return
      end

 

Прошу прощения, трудно писать на мобиле- живет своей жизнью, вопросительный знак отвергает))) Редактировать ошибки - проще застрелиться
Это оффтоп.

--- Сообщения объединены, Oct 8, 2013, Оригинальное время сообщения: Oct 8, 2013 ---

я у ТС просил фортран))))

 

Ага, ты ещё ассемблер у него попроси.

 

Да ладно вам, может он под мобилу че интересное пишет.

 

Lex K-G, на Java под мобилу, да :-) А на фортране только считать же, а не программы писать.

 

А что конкретно, если не секрет

 

В далёком 84-м. мною со товарищем, была написана программа вычисления эфемерид звёзд на момент наблюдения, а вы говорите только считать...
А кумпутеры какие были! ЕС1065, СМ-3...
Эх были времена....

 

Spoiler

А сколько на ём накоплено фунций для инженерных и научных рассчетов;) Да, еще и BERNEESE написан на Фортране.

 

Intel так не считает: Using Intel® Visual Fortran to Create and Build Windows*-Based Applications
Хотя вы правы, писать GUI на фортране — это ещё то извращение.

Spoiler

Хочу уточнить, программа вычисления эфемерид или приведения на видимое место? Или и то и другое?

Где-то чуть раньше принесли мне магнитную ленту с каталогом SAO (Smithsonian Astrophysical Observatory), о структуре которого ничего не было известно. На ЕС-ке лента читалась поблочно, но понять что к чему месяца два не мог. Пока не сообразил, что записана она была на машине, где в одном байте было шесть бит.

Когда в ЦГЧ поставили ЕС-1060, а затем расширили объём оперативной памяти до одного мегабайта, все не верили такому счастью, каждый в карточках JCL заказывал этот вожделенный мегабайт!
Некоторым через полгода работы машины мегабайта стало мало. Таких программистов начальник отделения майор Жидков в приказном порядке переводил на ЕС-1036, где было 256 Кб. И ставил задачу — через три месяца комплекс должен работать на ЕС-1036.
И вот, самое удивительное, не было никого, кто бы не справился с поставленной задачей!

Ну, для нормальной работы ещё Пёрл вроде бы был нужен. Для полного счастья не хватает 856000 рублей - цена коммерческой версии.
Радует, что увеличилось количество поддерживаемых трансляторов.
Кстати, GAMIT тоже почти весь на фортране.

 

Насколько я помню и то и другое. Хотя могу ошибаться - времени то прошло...

 

Spoiler

А можно ли где-то нарыть исходники оных? Пытался искать - не получилось...

 

Дядя Вова, не забывайте о таких вещах как сложность и скорость разработки) Быстро написать надёжную распределённую производительную расширяемую систему на фортране обломишься ведь. А вот JavaScript + node.js (внезапно), например, пожалуйста :-)
Lex K-G, таки почему вы спрашиваете? :-) Мобильный клиент для водителя к системе диспетчеризации транспортных средств.

--- Сообщения объединены, Oct 9, 2013, Оригинальное время сообщения: Oct 9, 2013 ---

Мы конечно думали на Erlang всё писать :-)

 

Spoiler

Для расширения кругозорности и вкурседельности в целях профилактики старомаразмости головных мозгов.)))